18x^2-10=3x

Solution for 18x^2-10=3x equation:

18x^2-10=3x

We move all terms to the left:

18x^2-10-(3x)=0

a = 18; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·18·(-10)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*18}=\frac{-24}{36}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*18}=\frac{30}{36}
=5/6
$